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14204423113 = 17609806657
BaseRepresentation
bin11010011101010011…
…00100101111001001
31100122221010110100221
431032221210233021
5213042313014423
610305254030041
71011666414166
oct151651445711
940587113327
1014204423113
11602a032361
122905048321
131454a844ba
1498a6cb06d
15582062e5d
hex34ea64bc9

14204423113 has 4 divisors (see below), whose sum is σ = 14205247380. Its totient is φ = 14203598848.

The previous prime is 14204423089. The next prime is 14204423171. The reversal of 14204423113 is 31132440241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6755524864 + 7448898249 = 82192^2 + 86307^2 .

It is a cyclic number.

It is not a de Polignac number, because 14204423113 - 29 = 14204422601 is a prime.

It is a super-2 number, since 2×142044231132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14204423183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385720 + ... + 420937.

It is an arithmetic number, because the mean of its divisors is an integer number (3551311845).

Almost surely, 214204423113 is an apocalyptic number.

It is an amenable number.

14204423113 is a deficient number, since it is larger than the sum of its proper divisors (824267).

14204423113 is an equidigital number, since it uses as much as digits as its factorization.

14204423113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 824266.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14204423113 its reverse (31132440241), we get a palindrome (45336863354).

The spelling of 14204423113 in words is "fourteen billion, two hundred four million, four hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 17609 806657 14204423113