Base | Representation |
---|---|
bin | 1100111010110011101010… |
… | …1111010010100101100111 |
3 | 1212021221011000020001012122 |
4 | 3032230322233102211213 |
5 | 3330211144213321203 |
6 | 50113233011340155 |
7 | 2664144215415341 |
oct | 316547257224547 |
9 | 55257130201178 |
10 | 14204442323303 |
11 | 4587085423061 |
12 | 1714ababb165b |
13 | 7c061c70429b |
14 | 3716da524291 |
15 | 19975436b538 |
hex | ceb3abd2967 |
14204442323303 has 4 divisors (see below), whose sum is σ = 14445195583080. Its totient is φ = 13963689063528.
The previous prime is 14204442323177. The next prime is 14204442323339. The reversal of 14204442323303 is 30332324440241.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-14204442323303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14204442323353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120376629800 + ... + 120376629917.
It is an arithmetic number, because the mean of its divisors is an integer number (3611298895770).
Almost surely, 214204442323303 is an apocalyptic number.
14204442323303 is a deficient number, since it is larger than the sum of its proper divisors (240753259777).
14204442323303 is an equidigital number, since it uses as much as digits as its factorization.
14204442323303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 240753259776.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 14204442323303 its reverse (30332324440241), we get a palindrome (44536766763544).
The spelling of 14204442323303 in words is "fourteen trillion, two hundred four billion, four hundred forty-two million, three hundred twenty-three thousand, three hundred three".
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