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14205540330103 = 22857976214699
BaseRepresentation
bin1100111010110111110000…
…1011110110101001110111
31212022000222112022120101011
43032231330023312221313
53330220421311030403
650113533553413051
72664213350340343
oct316557413665167
955260875276334
1014205540330103
1145875991a68a1
12171516686a187
137c0766037955
143717a22a4623
151997ba95ba6d
hexceb7c2f6a77

14205540330103 has 4 divisors (see below), whose sum is σ = 14205548830600. Its totient is φ = 14205531829608.

The previous prime is 14205540330061. The next prime is 14205540330127. The reversal of 14205540330103 is 30103304550241.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14205540330103 - 213 = 14205540321911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14205540330143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 821553 + ... + 5393146.

It is an arithmetic number, because the mean of its divisors is an integer number (3551387207650).

Almost surely, 214205540330103 is an apocalyptic number.

14205540330103 is a deficient number, since it is larger than the sum of its proper divisors (8500497).

14205540330103 is an equidigital number, since it uses as much as digits as its factorization.

14205540330103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8500496.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 14205540330103 its reverse (30103304550241), we get a palindrome (44308844880344).

The spelling of 14205540330103 in words is "fourteen trillion, two hundred five billion, five hundred forty million, three hundred thirty thousand, one hundred three".

Divisors: 1 2285797 6214699 14205540330103