Base | Representation |
---|---|
bin | 1100111011000111101011… |
… | …0000010101100000000001 |
3 | 1212022110000011220122120001 |
4 | 3032301322300111200001 |
5 | 3330303143143301442 |
6 | 50115521443320001 |
7 | 2664424241132512 |
oct | 316617260254001 |
9 | 55273004818501 |
10 | 14209811306497 |
11 | 4589390040654 |
12 | 1715b59080001 |
13 | 7c0c96b34711 |
14 | 371a895d4a09 |
15 | 19996a8ab2b7 |
hex | cec7ac15801 |
14209811306497 has 16 divisors (see below), whose sum is σ = 14693016002560. Its totient is φ = 13728163986000.
The previous prime is 14209811306413. The next prime is 14209811306507. The reversal of 14209811306497 is 79460311890241.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14209811306497 is a prime.
It is a super-2 number, since 2×142098113064972 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14209815306497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 158442454 + ... + 158532112.
It is an arithmetic number, because the mean of its divisors is an integer number (918313500160).
Almost surely, 214209811306497 is an apocalyptic number.
It is an amenable number.
14209811306497 is a deficient number, since it is larger than the sum of its proper divisors (483204696063).
14209811306497 is an equidigital number, since it uses as much as digits as its factorization.
14209811306497 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98284.
The product of its (nonzero) digits is 2612736, while the sum is 55.
The spelling of 14209811306497 in words is "fourteen trillion, two hundred nine billion, eight hundred eleven million, three hundred six thousand, four hundred ninety-seven".
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