Base | Representation |
---|---|
bin | 1100111011000111101011… |
… | …0000010101100000001011 |
3 | 1212022110000011220122120102 |
4 | 3032301322300111200023 |
5 | 3330303143143302012 |
6 | 50115521443320015 |
7 | 2664424241132525 |
oct | 316617260254013 |
9 | 55273004818512 |
10 | 14209811306507 |
11 | 4589390040663 |
12 | 1715b5908000b |
13 | 7c0c96b3471b |
14 | 371a895d4a15 |
15 | 19996a8ab2c2 |
hex | cec7ac1580b |
14209811306507 has 2 divisors, whose sum is σ = 14209811306508. Its totient is φ = 14209811306506.
The previous prime is 14209811306413. The next prime is 14209811306521. The reversal of 14209811306507 is 70560311890241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14209811306507 - 222 = 14209807112203 is a prime.
It is not a weakly prime, because it can be changed into another prime (14209811396507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7104905653253 + 7104905653254.
It is an arithmetic number, because the mean of its divisors is an integer number (7104905653254).
It is a 1-persistent number, because it is pandigital, but 2⋅14209811306507 = 28419622613014 is not.
Almost surely, 214209811306507 is an apocalyptic number.
14209811306507 is a deficient number, since it is larger than the sum of its proper divisors (1).
14209811306507 is an equidigital number, since it uses as much as digits as its factorization.
14209811306507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 47.
The spelling of 14209811306507 in words is "fourteen trillion, two hundred nine billion, eight hundred eleven million, three hundred six thousand, five hundred seven".
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