142100401 has 4 divisors (see below), whose sum is σ = 142131952. Its totient is φ = 142068852.

The previous prime is 142100393. The next prime is 142100407. The reversal of 142100401 is 104001241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104001241 = 83 ⋅1253027.

It is a cyclic number.

It is not a de Polignac number, because 142100401 - 2³ = 142100393 is a prime.

It is a super-3 number, since 3×142100401³ (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142100407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7611 + ... + 18496.

It is an arithmetic number, because the mean of its divisors is an integer number (35532988).

Almost surely, 2^142100401 is an apocalyptic number.

It is an amenable number.

142100401 is a deficient number, since it is larger than the sum of its proper divisors (31551).

142100401 is an equidigital number, since it uses as much as digits as its factorization.

142100401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31550.

The product of its (nonzero) digits is 32, while the sum is 13.

The square root of 142100401 is about 11920.5872758015. The cubic root of 142100401 is about 521.8332739704.

Adding to 142100401 its reverse (104001241), we get a palindrome (246101642).

The spelling of 142100401 in words is "one hundred forty-two million, one hundred thousand, four hundred one".