Base | Representation |
---|---|
bin | 1100111011001000110000… |
… | …1110011100101101101010 |
3 | 1212022110202121110000010201 |
4 | 3032302030032130231222 |
5 | 3330304243212204114 |
6 | 50120010513502414 |
7 | 2664434430401515 |
oct | 316621416345552 |
9 | 55273677400121 |
10 | 14210104413034 |
11 | 4589520536962 |
12 | 171601b271a0a |
13 | 7c101278a93a |
14 | 371ab64d1d7c |
15 | 1999864a7874 |
hex | cec8c39cb6a |
14210104413034 has 4 divisors (see below), whose sum is σ = 21315156619554. Its totient is φ = 7105052206516.
The previous prime is 14210104413017. The next prime is 14210104413061. The reversal of 14210104413034 is 43031440101241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13914369658809 + 295734754225 = 3730197^2 + 543815^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14210104412993 and 14210104413011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3552526103257 + ... + 3552526103260.
Almost surely, 214210104413034 is an apocalyptic number.
14210104413034 is a deficient number, since it is larger than the sum of its proper divisors (7105052206520).
14210104413034 is an equidigital number, since it uses as much as digits as its factorization.
14210104413034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7105052206519.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 14210104413034 its reverse (43031440101241), we get a palindrome (57241544514275).
The spelling of 14210104413034 in words is "fourteen trillion, two hundred ten billion, one hundred four million, four hundred thirteen thousand, thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •