Base | Representation |
---|---|
bin | 10100101011011100100… |
… | …111011101100111110001 |
3 | 12000211221202110222110111 |
4 | 110223130213131213301 |
5 | 141240242334241040 |
6 | 3004452250301321 |
7 | 204444465202462 |
oct | 24533447354761 |
9 | 5024852428414 |
10 | 1421040540145 |
11 | 4a872937a546 |
12 | 1ab4a7727841 |
13 | a4007a44325 |
14 | 4cac8b92d69 |
15 | 26e70418dea |
hex | 14adc9dd9f1 |
1421040540145 has 32 divisors (see below), whose sum is σ = 1777212576000. Its totient is φ = 1089785652480.
The previous prime is 1421040540091. The next prime is 1421040540151. The reversal of 1421040540145 is 5410450401241.
It is a de Polignac number, because none of the positive numbers 2k-1421040540145 is a prime.
It is a super-3 number, since 3×14210405401453 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19653279 + ... + 19725451.
It is an arithmetic number, because the mean of its divisors is an integer number (55537893000).
Almost surely, 21421040540145 is an apocalyptic number.
It is an amenable number.
1421040540145 is a deficient number, since it is larger than the sum of its proper divisors (356172035855).
1421040540145 is a wasteful number, since it uses less digits than its factorization.
1421040540145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73785.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 1421040540145 its reverse (5410450401241), we get a palindrome (6831490941386).
The spelling of 1421040540145 in words is "one trillion, four hundred twenty-one billion, forty million, five hundred forty thousand, one hundred forty-five".
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