1421104213033 has 4 divisors (see below), whose sum is σ = 1421188165008. Its totient is φ = 1421020261060.

The previous prime is 1421104213013. The next prime is 1421104213049. The reversal of 1421104213033 is 3303124011241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1421104213033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1421104212989 and 1421104213007.

It is not an unprimeable number, because it can be changed into a prime (1421104213003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41950591 + ... + 41984452.

It is an arithmetic number, because the mean of its divisors is an integer number (355297041252).

Almost surely, 2^{1421104213033} is an apocalyptic number.

It is an amenable number.

1421104213033 is a deficient number, since it is larger than the sum of its proper divisors (83951975).

1421104213033 is an equidigital number, since it uses as much as digits as its factorization.

1421104213033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83951974.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1421104213033 its reverse (3303124011241), we get a palindrome (4724228224274).

The spelling of 1421104213033 in words is "one trillion, four hundred twenty-one billion, one hundred four million, two hundred thirteen thousand, thirty-three".