142111104401403 has 32 divisors (see below), whose sum is σ = 210855975321600. Its totient is φ = 94596318903168.

The previous prime is 142111104401401. The next prime is 142111104401423. The reversal of 142111104401403 is 304104401111241.

142111104401403 is a `hidden beast` number, since 1 + 4 + 2 + 111 + 104 + 40 + 1 + 403 = 666.

It is not a de Polignac number, because 142111104401403 - 2¹ = 142111104401401 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (142111104401401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 145830150 + ... + 146801412.

It is an arithmetic number, because the mean of its divisors is an integer number (6589249228800).

Almost surely, 2^{142111104401403} is an apocalyptic number.

142111104401403 is a deficient number, since it is larger than the sum of its proper divisors (68744870920197).

142111104401403 is an equidigital number, since it uses as much as digits as its factorization.

142111104401403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 979528 (or 979522 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 27.

Adding to 142111104401403 its reverse (304104401111241), we get a palindrome (446215505512644).

The spelling of 142111104401403 in words is "one hundred forty-two trillion, one hundred eleven billion, one hundred four million, four hundred one thousand, four hundred three".