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1421112013 = 3145842323
BaseRepresentation
bin101010010110100…
…0111001011001101
310200001001222012021
41110231013023031
510402301041023
6353003210141
750134152466
oct12455071315
93601058167
101421112013
1166a1a9542
12337b16951
131985610a9
14d6a49d6d
1584b6535d
hex54b472cd

1421112013 has 4 divisors (see below), whose sum is σ = 1466954368. Its totient is φ = 1375269660.

The previous prime is 1421112001. The next prime is 1421112041. The reversal of 1421112013 is 3102111241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1421112013 - 25 = 1421111981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421112053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22921131 + ... + 22921192.

It is an arithmetic number, because the mean of its divisors is an integer number (366738592).

Almost surely, 21421112013 is an apocalyptic number.

It is an amenable number.

1421112013 is a deficient number, since it is larger than the sum of its proper divisors (45842355).

1421112013 is an equidigital number, since it uses as much as digits as its factorization.

1421112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45842354.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1421112013 is about 37697.6393558005. The cubic root of 1421112013 is about 1124.2841900434.

Adding to 1421112013 its reverse (3102111241), we get a palindrome (4523223254).

The spelling of 1421112013 in words is "one billion, four hundred twenty-one million, one hundred twelve thousand, thirteen".

Divisors: 1 31 45842323 1421112013