142111240140253 has 4 divisors (see below), whose sum is σ = 142194394758780. Its totient is φ = 142028085521728.

The previous prime is 142111240140151. The next prime is 142111240140281. The reversal of 142111240140253 is 352041042111241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11830999502884 + 130280240637369 = 3439622^2 + 11414037^2 .

It is a cyclic number.

It is not a de Polignac number, because 142111240140253 - 2²¹ = 142111238043101 is a prime.

It is a super-2 number, since 2×142111240140253² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142111240144253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41577306700 + ... + 41577310117.

It is an arithmetic number, because the mean of its divisors is an integer number (35548598689695).

Almost surely, 2^{142111240140253} is an apocalyptic number.

It is an amenable number.

142111240140253 is a deficient number, since it is larger than the sum of its proper divisors (83154618527).

142111240140253 is an equidigital number, since it uses as much as digits as its factorization.

142111240140253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83154618526.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 142111240140253 its reverse (352041042111241), we get a palindrome (494152282251494).

The spelling of 142111240140253 in words is "one hundred forty-two trillion, one hundred eleven billion, two hundred forty million, one hundred forty thousand, two hundred fifty-three".