142111434131 has 4 divisors (see below), whose sum is σ = 142112916000. Its totient is φ = 142109952264.

The previous prime is 142111434109. The next prime is 142111434151. The reversal of 142111434131 is 131434111241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131434111241 = 51419 ⋅2556139.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142111434131 is a prime.

It is a super-2 number, since 2×142111434131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142111434131.

It is not an unprimeable number, because it can be changed into a prime (142111434151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 586331 + ... + 792468.

It is an arithmetic number, because the mean of its divisors is an integer number (35528229000).

Almost surely, 2^142111434131 is an apocalyptic number.

142111434131 is a deficient number, since it is larger than the sum of its proper divisors (1481869).

142111434131 is a wasteful number, since it uses less digits than its factorization.

142111434131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1481868.

The product of its digits is 1152, while the sum is 26.

Adding to 142111434131 its reverse (131434111241), we get a palindrome (273545545372).

The spelling of 142111434131 in words is "one hundred forty-two billion, one hundred eleven million, four hundred thirty-four thousand, one hundred thirty-one".