142111434130 has 8 divisors (see below), whose sum is σ = 255800581452. Its totient is φ = 56844573648.

The previous prime is 142111434109. The next prime is 142111434151. The reversal of 142111434130 is 31434111241.

It is an interprime number because it is at equal distance from previous prime (142111434109) and next prime (142111434151).

It can be written as a sum of positive squares in 2 ways, for example, as 137023607889 + 5087826241 = 370167^2 + 71329^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 142111434095 and 142111434104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7105571697 + ... + 7105571716.

Almost surely, 2^142111434130 is an apocalyptic number.

142111434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

142111434130 is a deficient number, since it is larger than the sum of its proper divisors (113689147322).

142111434130 is a wasteful number, since it uses less digits than its factorization.

142111434130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14211143420.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 142111434130 its reverse (31434111241), we get a palindrome (173545545371).

The spelling of 142111434130 in words is "one hundred forty-two billion, one hundred eleven million, four hundred thirty-four thousand, one hundred thirty".