142113101402 has 4 divisors (see below), whose sum is σ = 213169652106. Its totient is φ = 71056550700.

The previous prime is 142113101401. The next prime is 142113101419. The reversal of 142113101402 is 204101311241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 204101311241 = 137 ⋅1489790593.

It can be written as a sum of positive squares in only one way, i.e., 90161472361 + 51951629041 = 300269^2 + 227929^2 .

It is a super-2 number, since 2×142113101402² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (142113101401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35528275349 + ... + 35528275352.

Almost surely, 2^142113101402 is an apocalyptic number.

142113101402 is a deficient number, since it is larger than the sum of its proper divisors (71056550704).

142113101402 is an equidigital number, since it uses as much as digits as its factorization.

142113101402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71056550703.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 142113101402 its reverse (204101311241), we get a palindrome (346214412643).

The spelling of 142113101402 in words is "one hundred forty-two billion, one hundred thirteen million, one hundred one thousand, four hundred two".