142114433001 has 4 divisors (see below), whose sum is σ = 189485910672. Its totient is φ = 94742955332.

The previous prime is 142114432939. The next prime is 142114433093. The reversal of 142114433001 is 100334411241.

142114433001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142114433001 - 2³³ = 133524498409 is a prime.

It is not an unprimeable number, because it can be changed into a prime (142114433501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23685738831 + ... + 23685738836.

It is an arithmetic number, because the mean of its divisors is an integer number (47371477668).

Almost surely, 2^142114433001 is an apocalyptic number.

It is an amenable number.

142114433001 is a deficient number, since it is larger than the sum of its proper divisors (47371477671).

142114433001 is an equidigital number, since it uses as much as digits as its factorization.

142114433001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47371477670.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 142114433001 its reverse (100334411241), we get a palindrome (242448844242).

The spelling of 142114433001 in words is "one hundred forty-two billion, one hundred fourteen million, four hundred thirty-three thousand, one".