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1421154350000 = 2455721152733
BaseRepresentation
bin10100101011100011011…
…001100111001110110000
312000212020200122010020022
4110223203121213032300
5141241011003200000
63004511433503012
7204450346442600
oct24534331471660
95025220563208
101421154350000
114a8787643580
121ab519871a68
13a40254b1838
144cad9d3ac00
1526e7a3ea585
hex14ae36673b0

1421154350000 has 360 divisors, whose sum is σ = 4367578800816. Its totient is φ = 442948800000.

The previous prime is 1421154349987. The next prime is 1421154350089. The reversal of 1421154350000 is 534511241.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 26923634 + ... + 26976366.

Almost surely, 21421154350000 is an apocalyptic number.

1421154350000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1421154350000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2183789400408).

1421154350000 is an abundant number, since it is smaller than the sum of its proper divisors (2946424450816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1421154350000 is an equidigital number, since it uses as much as digits as its factorization.

1421154350000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52791 (or 52758 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 1421154350000 its reverse (534511241), we get a palindrome (1421688861241).

The spelling of 1421154350000 in words is "one trillion, four hundred twenty-one billion, one hundred fifty-four million, three hundred fifty thousand".