142120134434101 has 4 divisors (see below), whose sum is σ = 149600141509600. Its totient is φ = 134640127358604.

The previous prime is 142120134434081. The next prime is 142120134434123. The reversal of 142120134434101 is 101434431021241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142120134434101 - 2³¹ = 142117986950453 is a prime.

It is a super-2 number, since 2×142120134434101² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142120134431101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3740003537721 + ... + 3740003537758.

It is an arithmetic number, because the mean of its divisors is an integer number (37400035377400).

Almost surely, 2^{142120134434101} is an apocalyptic number.

It is an amenable number.

142120134434101 is a deficient number, since it is larger than the sum of its proper divisors (7480007075499).

142120134434101 is an equidigital number, since it uses as much as digits as its factorization.

142120134434101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7480007075498.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 142120134434101 its reverse (101434431021241), we get a palindrome (243554565455342).

The spelling of 142120134434101 in words is "one hundred forty-two trillion, one hundred twenty billion, one hundred thirty-four million, four hundred thirty-four thousand, one hundred one".