Base | Representation |
---|---|
bin | 1000010001011100010… |
… | …0101010111111111001 |
3 | 111120211122202221011120 |
4 | 2010113010222333321 |
5 | 4312030440141213 |
6 | 145142310415453 |
7 | 13160614515156 |
oct | 2042704527771 |
9 | 446748687146 |
10 | 142121021433 |
11 | 5530067aa16 |
12 | 23664061589 |
13 | 1052c130171 |
14 | 6c431cb22d |
15 | 3a6c03c423 |
hex | 211712aff9 |
142121021433 has 24 divisors (see below), whose sum is σ = 196382042688. Its totient is φ = 91420663488.
The previous prime is 142121021407. The next prime is 142121021443. The reversal of 142121021433 is 334120121241.
It is not a de Polignac number, because 142121021433 - 213 = 142121013241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (142121021443) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4036935 + ... + 4071987.
It is an arithmetic number, because the mean of its divisors is an integer number (8182585112).
Almost surely, 2142121021433 is an apocalyptic number.
It is an amenable number.
142121021433 is a deficient number, since it is larger than the sum of its proper divisors (54261021255).
142121021433 is a wasteful number, since it uses less digits than its factorization.
142121021433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36721 (or 36692 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 142121021433 its reverse (334120121241), we get a palindrome (476241142674).
The spelling of 142121021433 in words is "one hundred forty-two billion, one hundred twenty-one million, twenty-one thousand, four hundred thirty-three".
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