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1421214303 = 3641739061
BaseRepresentation
bin101010010110110…
…0000001001011111
310200001021011111210
41110231200021133
510402312324203
6353005315503
750135056635
oct12455401137
93601234453
101421214303
1166a269383
12337b65b93
13198598812
14d6a75355
1584b85803
hex54b6025f

1421214303 has 8 divisors (see below), whose sum is σ = 1897911216. Its totient is φ = 945996800.

The previous prime is 1421214293. The next prime is 1421214323. The reversal of 1421214303 is 3034121241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1421214303 - 25 = 1421214271 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1421214303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421214323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 367608 + ... + 371453.

It is an arithmetic number, because the mean of its divisors is an integer number (237238902).

Almost surely, 21421214303 is an apocalyptic number.

1421214303 is a deficient number, since it is larger than the sum of its proper divisors (476696913).

1421214303 is an equidigital number, since it uses as much as digits as its factorization.

1421214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 739705.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1421214303 is about 37698.9960476403. The cubic root of 1421214303 is about 1124.3111642884.

Adding to 1421214303 its reverse (3034121241), we get a palindrome (4455335544).

The spelling of 1421214303 in words is "one billion, four hundred twenty-one million, two hundred fourteen thousand, three hundred three".

Divisors: 1 3 641 1923 739061 2217183 473738101 1421214303