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142122131331 = 347374043777
BaseRepresentation
bin1000010001011100100…
…0111001111110000011
3111120211201212022122220
42010113020321332003
54312031231200311
6145142350302123
713160630120055
oct2042710717603
9446751768586
10142122131331
1155301268894
12236644b7943
131052c42b3cb
146c433d98d5
153a6c1ab206
hex2117239f83

142122131331 has 4 divisors (see below), whose sum is σ = 189496175112. Its totient is φ = 94748087552.

The previous prime is 142122131317. The next prime is 142122131423. The reversal of 142122131331 is 133131221241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142122131331 - 25 = 142122131299 is a prime.

It is a super-2 number, since 2×1421221313312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (142122131731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23687021886 + ... + 23687021891.

It is an arithmetic number, because the mean of its divisors is an integer number (47374043778).

Almost surely, 2142122131331 is an apocalyptic number.

142122131331 is a deficient number, since it is larger than the sum of its proper divisors (47374043781).

142122131331 is an equidigital number, since it uses as much as digits as its factorization.

142122131331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47374043780.

The product of its digits is 864, while the sum is 24.

Adding to 142122131331 its reverse (133131221241), we get a palindrome (275253352572).

The spelling of 142122131331 in words is "one hundred forty-two billion, one hundred twenty-two million, one hundred thirty-one thousand, three hundred thirty-one".

Divisors: 1 3 47374043777 142122131331