Search a number
-
+
14212410423433 = 17597807660989
BaseRepresentation
bin1100111011010001010110…
…1011001011100010001001
31212022200201022121110201021
43032310111223023202021
53330324004032022213
650121031411352441
72664545531225065
oct316642553134211
955280638543637
1014212410423433
11458a4a4192682
1217165635b2721
137c12bc458731
14371c54886aa5
15199a6db64d8d
hexced15acb889

14212410423433 has 4 divisors (see below), whose sum is σ = 14213218102020. Its totient is φ = 14211602744848.

The previous prime is 14212410423383. The next prime is 14212410423443. The reversal of 14212410423433 is 33432401421241.

14212410423433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 983244778569 + 13229165644864 = 991587^2 + 3637192^2 .

It is a cyclic number.

It is not a de Polignac number, because 14212410423433 - 217 = 14212410292361 is a prime.

It is a super-2 number, since 2×142124104234332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14212410423443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403812898 + ... + 403848091.

It is an arithmetic number, because the mean of its divisors is an integer number (3553304525505).

Almost surely, 214212410423433 is an apocalyptic number.

It is an amenable number.

14212410423433 is a deficient number, since it is larger than the sum of its proper divisors (807678587).

14212410423433 is an equidigital number, since it uses as much as digits as its factorization.

14212410423433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 807678586.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 14212410423433 its reverse (33432401421241), we get a palindrome (47644811844674).

The spelling of 14212410423433 in words is "fourteen trillion, two hundred twelve billion, four hundred ten million, four hundred twenty-three thousand, four hundred thirty-three".

Divisors: 1 17597 807660989 14212410423433