Base | Representation |
---|---|
bin | 11010011110010000… |
… | …00101011100011011 |
3 | 1100200111011210221220 |
4 | 31033020011130123 |
5 | 213101334441103 |
6 | 10310141303123 |
7 | 1012124405625 |
oct | 151710053433 |
9 | 40614153856 |
10 | 14212421403 |
11 | 60335a5614 |
12 | 2907864aa3 |
13 | 1456624c0b |
14 | 98b7adc15 |
15 | 582ae2c53 |
hex | 34f20571b |
14212421403 has 16 divisors (see below), whose sum is σ = 18999520800. Its totient is φ = 9450169344.
The previous prime is 14212421381. The next prime is 14212421407. The reversal of 14212421403 is 30412421241.
14212421403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14212421403 - 25 = 14212421371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14212421407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2041773 + ... + 2048721.
It is an arithmetic number, because the mean of its divisors is an integer number (1187470050).
Almost surely, 214212421403 is an apocalyptic number.
14212421403 is a deficient number, since it is larger than the sum of its proper divisors (4787099397).
14212421403 is a wasteful number, since it uses less digits than its factorization.
14212421403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8638.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 14212421403 its reverse (30412421241), we get a palindrome (44624842644).
The spelling of 14212421403 in words is "fourteen billion, two hundred twelve million, four hundred twenty-one thousand, four hundred three".
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