Base | Representation |
---|---|
bin | 100000010100001011101010… |
… | …011001001111111101000011 |
3 | 200122012221220211020000112002 |
4 | 200110023222121033331003 |
5 | 122112031232434442011 |
6 | 1222135014222254215 |
7 | 41636102063014646 |
oct | 4024135231177503 |
9 | 618187824200462 |
10 | 142124400312131 |
11 | 4131568a889846 |
12 | 13b347b212736b |
13 | 613c3729a1203 |
14 | 2714c0167da5d |
15 | 1166ead91ac3b |
hex | 8142ea64ff43 |
142124400312131 has 8 divisors (see below), whose sum is σ = 142289380992000. Its totient is φ = 141959463113160.
The previous prime is 142124400312127. The next prime is 142124400312133. The reversal of 142124400312131 is 131213004421241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 142124400312131 - 22 = 142124400312127 is a prime.
It is a super-2 number, since 2×1421244003121312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142124400312094 and 142124400312103.
It is not an unprimeable number, because it can be changed into a prime (142124400312133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4326821 + ... + 17406038.
It is an arithmetic number, because the mean of its divisors is an integer number (17786172624000).
Almost surely, 2142124400312131 is an apocalyptic number.
142124400312131 is a deficient number, since it is larger than the sum of its proper divisors (164980679869).
142124400312131 is an equidigital number, since it uses as much as digits as its factorization.
142124400312131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21740449.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 142124400312131 its reverse (131213004421241), we get a palindrome (273337404733372).
The spelling of 142124400312131 in words is "one hundred forty-two trillion, one hundred twenty-four billion, four hundred million, three hundred twelve thousand, one hundred thirty-one".
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