14212551253 has 4 divisors (see below), whose sum is σ = 14830488288. Its totient is φ = 13594614220.

The previous prime is 14212551251. The next prime is 14212551257. The reversal of 14212551253 is 35215521241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14212551253 - 2¹ = 14212551251 is a prime.

It is a super-2 number, since 2×14212551253² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14212551251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308968483 + ... + 308968528.

It is an arithmetic number, because the mean of its divisors is an integer number (3707622072).

Almost surely, 2^14212551253 is an apocalyptic number.

It is an amenable number.

14212551253 is a deficient number, since it is larger than the sum of its proper divisors (617937035).

14212551253 is an equidigital number, since it uses as much as digits as its factorization.

14212551253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617937034.

The product of its digits is 12000, while the sum is 31.

The spelling of 14212551253 in words is "fourteen billion, two hundred twelve million, five hundred fifty-one thousand, two hundred fifty-three".