1421300044321 has 4 divisors (see below), whose sum is σ = 1421737236144. Its totient is φ = 1420862852500.

The previous prime is 1421300044309. The next prime is 1421300044327. The reversal of 1421300044321 is 1234400031241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1421300044321 - 2¹⁵ = 1421300011553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1421300044327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218591035 + ... + 218597536.

It is an arithmetic number, because the mean of its divisors is an integer number (355434309036).

Almost surely, 2^{1421300044321} is an apocalyptic number.

It is an amenable number.

1421300044321 is a deficient number, since it is larger than the sum of its proper divisors (437191823).

1421300044321 is an equidigital number, since it uses as much as digits as its factorization.

1421300044321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437191822.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1421300044321 its reverse (1234400031241), we get a palindrome (2655700075562).

The spelling of 1421300044321 in words is "one trillion, four hundred twenty-one billion, three hundred million, forty-four thousand, three hundred twenty-one".