Base | Representation |
---|---|
bin | 10100101011101100000… |
… | …110110000100011100010 |
3 | 12000212121212110100110112 |
4 | 110223230012300203202 |
5 | 141241310400334102 |
6 | 3004534132131322 |
7 | 204454102041416 |
oct | 24535406604342 |
9 | 5025555410415 |
10 | 1421300402402 |
11 | 4a8852029941 |
12 | 1ab55a766b42 |
13 | a404982a98a |
14 | 4cb114b8d46 |
15 | 26e8814a252 |
hex | 14aec1b08e2 |
1421300402402 has 4 divisors (see below), whose sum is σ = 2131950603606. Its totient is φ = 710650201200.
The previous prime is 1421300402381. The next prime is 1421300402407. The reversal of 1421300402402 is 2042040031241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 835357612441 + 585942789961 = 913979^2 + 765469^2 .
It is not an unprimeable number, because it can be changed into a prime (1421300402407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 355325100599 + ... + 355325100602.
Almost surely, 21421300402402 is an apocalyptic number.
1421300402402 is a deficient number, since it is larger than the sum of its proper divisors (710650201204).
1421300402402 is an equidigital number, since it uses as much as digits as its factorization.
1421300402402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710650201203.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 1421300402402 its reverse (2042040031241), we get a palindrome (3463340433643).
The spelling of 1421300402402 in words is "one trillion, four hundred twenty-one billion, three hundred million, four hundred two thousand, four hundred two".
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