142131411344001 has 4 divisors (see below), whose sum is σ = 189508548458672. Its totient is φ = 94754274229332.

The previous prime is 142131411343973. The next prime is 142131411344023. The reversal of 142131411344001 is 100443114131241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 142131411344001 - 2¹⁵ = 142131411311233 is a prime.

It is a super-2 number, since 2×142131411344001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142131411344001.

It is not an unprimeable number, because it can be changed into a prime (142131411340001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23688568557331 + ... + 23688568557336.

It is an arithmetic number, because the mean of its divisors is an integer number (47377137114668).

Almost surely, 2^{142131411344001} is an apocalyptic number.

It is an amenable number.

142131411344001 is a deficient number, since it is larger than the sum of its proper divisors (47377137114671).

142131411344001 is an equidigital number, since it uses as much as digits as its factorization.

142131411344001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47377137114670.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 142131411344001 its reverse (100443114131241), we get a palindrome (242574525475242).

The spelling of 142131411344001 in words is "one hundred forty-two trillion, one hundred thirty-one billion, four hundred eleven million, three hundred forty-four thousand, one".