14213141212001 has 4 divisors (see below), whose sum is σ = 14213164547604. Its totient is φ = 14213117876400.

The previous prime is 14213141211977. The next prime is 14213141212027. The reversal of 14213141212001 is 10021214131241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6148535181376 + 8064606030625 = 2479624^2 + 2839825^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213141212001 - 2¹⁸ = 14213140949857 is a prime.

It is a super-2 number, since 2×14213141212001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14213141212051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10729010 + ... + 11980731.

It is an arithmetic number, because the mean of its divisors is an integer number (3553291136901).

Almost surely, 2^{14213141212001} is an apocalyptic number.

It is an amenable number.

14213141212001 is a deficient number, since it is larger than the sum of its proper divisors (23335603).

14213141212001 is an equidigital number, since it uses as much as digits as its factorization.

14213141212001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23335602.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 14213141212001 its reverse (10021214131241), we get a palindrome (24234355343242).

The spelling of 14213141212001 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-one million, two hundred twelve thousand, one".