Search a number
-
+
14213141212027 is a prime number
BaseRepresentation
bin1100111011010100000100…
…1110111010101101111011
31212022202121020201101012111
43032311001032322231323
53330332003122241102
650121232114553151
72664602613641062
oct316650116725573
955282536641174
1014213141212027
11458a83975099a
1217167282987b7
137c13a7987a14
14371cc39571d9
15199ab2db9cd7
hexced413bab7b

14213141212027 has 2 divisors, whose sum is σ = 14213141212028. Its totient is φ = 14213141212026.

The previous prime is 14213141211977. The next prime is 14213141212051. The reversal of 14213141212027 is 72021214131241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14213141212027 is a prime.

It is a super-2 number, since 2×142131412120272 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14213141212027.

It is not a weakly prime, because it can be changed into another prime (14213141212097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106570606013 + 7106570606014.

It is an arithmetic number, because the mean of its divisors is an integer number (7106570606014).

Almost surely, 214213141212027 is an apocalyptic number.

14213141212027 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213141212027 is an equidigital number, since it uses as much as digits as its factorization.

14213141212027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 31.

Adding to 14213141212027 its reverse (72021214131241), we get a palindrome (86234355343268).

The spelling of 14213141212027 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-one million, two hundred twelve thousand, twenty-seven".