Base | Representation |
---|---|
bin | 1100111011010100000101… |
… | …0111010110100110111111 |
3 | 1212022202121101212201200001 |
4 | 3032311001113112212333 |
5 | 3330332004204022143 |
6 | 50121232234215131 |
7 | 2664602641511230 |
oct | 316650127264677 |
9 | 55282541781601 |
10 | 14213143423423 |
11 | 458a83aa2139a |
12 | 1716728b844a7 |
13 | 7c13a8280439 |
14 | 371cc3d71087 |
15 | 199ab31a514d |
hex | ced415d69bf |
14213143423423 has 8 divisors (see below), whose sum is σ = 16244027138592. Its totient is φ = 12182368371936.
The previous prime is 14213143423267. The next prime is 14213143423447. The reversal of 14213143423423 is 32432434131241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-14213143423423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14213143423123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26885440 + ... + 27408997.
It is an arithmetic number, because the mean of its divisors is an integer number (2030503392324).
Almost surely, 214213143423423 is an apocalyptic number.
14213143423423 is a deficient number, since it is larger than the sum of its proper divisors (2030883715169).
14213143423423 is an equidigital number, since it uses as much as digits as its factorization.
14213143423423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54331841.
The product of its digits is 165888, while the sum is 37.
Adding to 14213143423423 its reverse (32432434131241), we get a palindrome (46645577554664).
The spelling of 14213143423423 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-three million, four hundred twenty-three thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •