14213212112041 has 4 divisors (see below), whose sum is σ = 14597352979972. Its totient is φ = 13829071244112.

The previous prime is 14213212112017. The next prime is 14213212112051. The reversal of 14213212112041 is 14021121231241.

14213212112041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7618588112041 + 6594624000000 = 2760179^2 + 2568000^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213212112041 - 2²⁹ = 14212675241129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14213212111997 and 14213212112015.

It is not an unprimeable number, because it can be changed into a prime (14213212112051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192070433910 + ... + 192070433983.

It is an arithmetic number, because the mean of its divisors is an integer number (3649338244993).

Almost surely, 2^{14213212112041} is an apocalyptic number.

It is an amenable number.

14213212112041 is a deficient number, since it is larger than the sum of its proper divisors (384140867931).

14213212112041 is an equidigital number, since it uses as much as digits as its factorization.

14213212112041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 384140867930.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14213212112041 its reverse (14021121231241), we get a palindrome (28234333343282).

The spelling of 14213212112041 in words is "fourteen trillion, two hundred thirteen billion, two hundred twelve million, one hundred twelve thousand, forty-one".