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1421323414113 = 3637937426747
BaseRepresentation
bin10100101011101101011…
…110100010101001100001
312000212200110202110121010
4110223231132202221201
5141241332243222423
63004540313251133
7204454501453101
oct24535536425141
95025613673533
101421323414113
114a8864016989
121ab566403aa9
13a4051526b85
144cb14589201
1526e8a193693
hex14aed7a2a61

1421323414113 has 8 divisors (see below), whose sum is σ = 1895127847648. Its totient is φ = 947533961664.

The previous prime is 1421323414111. The next prime is 1421323414129. The reversal of 1421323414113 is 3114143231241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1421323414113 - 21 = 1421323414111 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1421323414111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3521995 + ... + 3904752.

It is an arithmetic number, because the mean of its divisors is an integer number (236890980956).

Almost surely, 21421323414113 is an apocalyptic number.

It is an amenable number.

1421323414113 is a deficient number, since it is larger than the sum of its proper divisors (473804433535).

1421323414113 is an equidigital number, since it uses as much as digits as its factorization.

1421323414113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7490543.

The product of its digits is 6912, while the sum is 30.

Adding to 1421323414113 its reverse (3114143231241), we get a palindrome (4535466645354).

The spelling of 1421323414113 in words is "one trillion, four hundred twenty-one billion, three hundred twenty-three million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 63793 191379 7426747 22280241 473774471371 1421323414113