Base | Representation |
---|---|
bin | 1000010001011111010… |
… | …0111010011011011111 |
3 | 111120212112120102101022 |
4 | 2010113310322123133 |
5 | 4312042204330201 |
6 | 145143441434355 |
7 | 13161130145261 |
oct | 2042764723337 |
9 | 446775512338 |
10 | 142133667551 |
11 | 55307828157 |
12 | 2366833b9bb |
13 | 1053193a285 |
14 | 6c44b5db31 |
15 | 3a6d1d941b |
hex | 2117d3a6df |
142133667551 has 4 divisors (see below), whose sum is σ = 142137249600. Its totient is φ = 142130085504.
The previous prime is 142133667451. The next prime is 142133667587. The reversal of 142133667551 is 155766331241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155766331241 = 1277 ⋅121978333.
It is a cyclic number.
It is not a de Polignac number, because 142133667551 - 234 = 124953798367 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142133667451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1730831 + ... + 1811088.
It is an arithmetic number, because the mean of its divisors is an integer number (35534312400).
Almost surely, 2142133667551 is an apocalyptic number.
142133667551 is a deficient number, since it is larger than the sum of its proper divisors (3582049).
142133667551 is an equidigital number, since it uses as much as digits as its factorization.
142133667551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3582048.
The product of its digits is 453600, while the sum is 44.
Adding to 142133667551 its reverse (155766331241), we get a palindrome (297899998792).
The spelling of 142133667551 in words is "one hundred forty-two billion, one hundred thirty-three million, six hundred sixty-seven thousand, five hundred fifty-one".
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