Base | Representation |
---|---|
bin | 101010010110111… |
… | …1111000111100011 |
3 | 10200001111121112000 |
4 | 1110231333013203 |
5 | 10402330404110 |
6 | 353012135043 |
7 | 50136125523 |
oct | 12455770743 |
9 | 3601447460 |
10 | 1421341155 |
11 | 66a345713 |
12 | 338007483 |
13 | 198611490 |
14 | d6aa9683 |
15 | 84bad1c0 |
hex | 54b7f1e3 |
1421341155 has 64 divisors (see below), whose sum is σ = 2728427520. Its totient is φ = 697880448.
The previous prime is 1421341153. The next prime is 1421341169. The reversal of 1421341155 is 5511431241.
It is not a de Polignac number, because 1421341155 - 21 = 1421341153 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (1421341153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 853854 + ... + 855516.
It is an arithmetic number, because the mean of its divisors is an integer number (42631680).
Almost surely, 21421341155 is an apocalyptic number.
1421341155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1421341155 is a deficient number, since it is larger than the sum of its proper divisors (1307086365).
1421341155 is a wasteful number, since it uses less digits than its factorization.
1421341155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2177 (or 2171 counting only the distinct ones).
The product of its digits is 2400, while the sum is 27.
The square root of 1421341155 is about 37700.6784421713. The cubic root of 1421341155 is about 1124.3446138243.
Adding to 1421341155 its reverse (5511431241), we get a palindrome (6932772396).
The spelling of 1421341155 in words is "one billion, four hundred twenty-one million, three hundred forty-one thousand, one hundred fifty-five".
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