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14213440103 = 72131970531
BaseRepresentation
bin11010011110010111…
…11110001001100111
31100200120002120100112
431033023332021213
5213102120040403
610310215203235
71012136150612
oct151713761147
940616076315
1014213440103
116034130a15
12290807651b
1314568c07b5
1498b997179
15582c449d8
hex34f2fe267

14213440103 has 4 divisors (see below), whose sum is σ = 14215417848. Its totient is φ = 14211462360.

The previous prime is 14213440081. The next prime is 14213440169. The reversal of 14213440103 is 30104431241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30104431241 = 36782028423.

It is a cyclic number.

It is not a de Polignac number, because 14213440103 - 26 = 14213440039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14213440403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 978053 + ... + 992478.

It is an arithmetic number, because the mean of its divisors is an integer number (3553854462).

Almost surely, 214213440103 is an apocalyptic number.

14213440103 is a deficient number, since it is larger than the sum of its proper divisors (1977745).

14213440103 is an equidigital number, since it uses as much as digits as its factorization.

14213440103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1977744.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14213440103 its reverse (30104431241), we get a palindrome (44317871344).

The spelling of 14213440103 in words is "fourteen billion, two hundred thirteen million, four hundred forty thousand, one hundred three".

Divisors: 1 7213 1970531 14213440103