Base | Representation |
---|---|
bin | 100000010100010110000000… |
… | …001000011011110011111101 |
3 | 200122021000120112210121010112 |
4 | 200110112000020123303331 |
5 | 122112222002104434440 |
6 | 1222144052015115405 |
7 | 41636644152256004 |
oct | 4024260010336375 |
9 | 618230515717115 |
10 | 142135502421245 |
11 | 4131a367719733 |
12 | 13b36990212b65 |
13 | 6140421aca348 |
14 | 2715575d2dc3b |
15 | 116740d429965 |
hex | 81458021bcfd |
142135502421245 has 16 divisors (see below), whose sum is σ = 170665775280000. Its totient is φ = 113639641176768.
The previous prime is 142135502421239. The next prime is 142135502421251. The reversal of 142135502421245 is 542124205531241.
It is an interprime number because it is at equal distance from previous prime (142135502421239) and next prime (142135502421251).
It is a cyclic number.
It is not a de Polignac number, because 142135502421245 - 24 = 142135502421229 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53448791 + ... + 56045019.
It is an arithmetic number, because the mean of its divisors is an integer number (10666610955000).
Almost surely, 2142135502421245 is an apocalyptic number.
It is an amenable number.
142135502421245 is a deficient number, since it is larger than the sum of its proper divisors (28530272858755).
142135502421245 is a wasteful number, since it uses less digits than its factorization.
142135502421245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2602852.
The product of its (nonzero) digits is 384000, while the sum is 41.
Adding to 142135502421245 its reverse (542124205531241), we get a palindrome (684259707952486).
The spelling of 142135502421245 in words is "one hundred forty-two trillion, one hundred thirty-five billion, five hundred two million, four hundred twenty-one thousand, two hundred forty-five".
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