Base | Representation |
---|---|
bin | 1100111011010101100110… |
… | …1110100010010110111011 |
3 | 1212022210122212222101200011 |
4 | 3032311121232202112323 |
5 | 3330333323322412133 |
6 | 50121340554522351 |
7 | 2664616033614544 |
oct | 316653156422673 |
9 | 55283585871604 |
10 | 14213552154043 |
11 | 458aa2a70a7a0 |
12 | 1716821a363b7 |
13 | 7c1441b5a888 |
14 | 371d223694cb |
15 | 199ad8ee06cd |
hex | ced59ba25bb |
14213552154043 has 32 divisors (see below), whose sum is σ = 16804275351552. Its totient is φ = 11878279603200.
The previous prime is 14213552154007. The next prime is 14213552154089. The reversal of 14213552154043 is 34045125531241.
It is not a de Polignac number, because 14213552154043 - 221 = 14213550056891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14213552153987 and 14213552154005.
It is not an unprimeable number, because it can be changed into a prime (14213552154443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3648363 + ... + 6460468.
It is an arithmetic number, because the mean of its divisors is an integer number (525133604736).
Almost surely, 214213552154043 is an apocalyptic number.
14213552154043 is a deficient number, since it is larger than the sum of its proper divisors (2590723197509).
14213552154043 is a wasteful number, since it uses less digits than its factorization.
14213552154043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10109035.
The product of its (nonzero) digits is 288000, while the sum is 40.
Adding to 14213552154043 its reverse (34045125531241), we get a palindrome (48258677685284).
The spelling of 14213552154043 in words is "fourteen trillion, two hundred thirteen billion, five hundred fifty-two million, one hundred fifty-four thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •