Base | Representation |
---|---|
bin | 1000010001100000110… |
… | …1001010000011111011 |
3 | 111120212222112022110121 |
4 | 2010120031022003323 |
5 | 4312100321214120 |
6 | 145144225554111 |
7 | 13161235155343 |
oct | 2043015120373 |
9 | 446788468417 |
10 | 142140023035 |
11 | 5531037911a |
12 | 2366a4a5937 |
13 | 1053305400a |
14 | 6c45935d23 |
15 | 3a6da425aa |
hex | 211834a0fb |
142140023035 has 4 divisors (see below), whose sum is σ = 170568027648. Its totient is φ = 113712018424.
The previous prime is 142140023009. The next prime is 142140023041. The reversal of 142140023035 is 530320041241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530320041241 = 821 ⋅645944021.
It is a cyclic number.
It is not a de Polignac number, because 142140023035 - 211 = 142140020987 is a prime.
It is a super-2 number, since 2×1421400230352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14214002299 + ... + 14214002308.
It is an arithmetic number, because the mean of its divisors is an integer number (42642006912).
Almost surely, 2142140023035 is an apocalyptic number.
142140023035 is a deficient number, since it is larger than the sum of its proper divisors (28428004613).
142140023035 is an equidigital number, since it uses as much as digits as its factorization.
142140023035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28428004612.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 142140023035 its reverse (530320041241), we get a palindrome (672460064276).
The spelling of 142140023035 in words is "one hundred forty-two billion, one hundred forty million, twenty-three thousand, thirty-five".
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