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142140023035 = 528428004607
BaseRepresentation
bin1000010001100000110…
…1001010000011111011
3111120212222112022110121
42010120031022003323
54312100321214120
6145144225554111
713161235155343
oct2043015120373
9446788468417
10142140023035
115531037911a
122366a4a5937
131053305400a
146c45935d23
153a6da425aa
hex211834a0fb

142140023035 has 4 divisors (see below), whose sum is σ = 170568027648. Its totient is φ = 113712018424.

The previous prime is 142140023009. The next prime is 142140023041. The reversal of 142140023035 is 530320041241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530320041241 = 821645944021.

It is a cyclic number.

It is not a de Polignac number, because 142140023035 - 211 = 142140020987 is a prime.

It is a super-2 number, since 2×1421400230352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14214002299 + ... + 14214002308.

It is an arithmetic number, because the mean of its divisors is an integer number (42642006912).

Almost surely, 2142140023035 is an apocalyptic number.

142140023035 is a deficient number, since it is larger than the sum of its proper divisors (28428004613).

142140023035 is an equidigital number, since it uses as much as digits as its factorization.

142140023035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28428004612.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 142140023035 its reverse (530320041241), we get a palindrome (672460064276).

The spelling of 142140023035 in words is "one hundred forty-two billion, one hundred forty million, twenty-three thousand, thirty-five".

Divisors: 1 5 28428004607 142140023035