14214003200103 has 8 divisors (see below), whose sum is σ = 21659433447808. Its totient is φ = 8122287542904.

The previous prime is 14214003200101. The next prime is 14214003200119. The reversal of 14214003200103 is 30100230041241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14214003200103 - 2¹ = 14214003200101 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 676857295243 = 14214003200103 / (1 + 4 + 2 + 1 + 4 + 0 + 0 + 3 + 2 + 0 + 0 + 1 + 0 + 3).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14214003200103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14214003200101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 338428647601 + ... + 338428647642.

It is an arithmetic number, because the mean of its divisors is an integer number (2707429180976).

Almost surely, 2^{14214003200103} is an apocalyptic number.

14214003200103 is a deficient number, since it is larger than the sum of its proper divisors (7445430247705).

14214003200103 is an equidigital number, since it uses as much as digits as its factorization.

14214003200103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 676857295253.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14214003200103 its reverse (30100230041241), we get a palindrome (44314233241344).

The spelling of 14214003200103 in words is "fourteen trillion, two hundred fourteen billion, three million, two hundred thousand, one hundred three".