Base | Representation |
---|---|
bin | 11010011110011101… |
… | …11111110000101011 |
3 | 1100200121120212011221 |
4 | 31033032333300223 |
5 | 213102320430011 |
6 | 10310244202511 |
7 | 1012145662630 |
oct | 151716776053 |
9 | 40617525157 |
10 | 14214233131 |
11 | 603462280a |
12 | 2908399437 |
13 | 1456b0a747 |
14 | 98bb22187 |
15 | 582d4e971 |
hex | 34f3bfc2b |
14214233131 has 8 divisors (see below), whose sum is σ = 16683887840. Its totient is φ = 11854340928.
The previous prime is 14214233087. The next prime is 14214233141. The reversal of 14214233131 is 13133241241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14214233131 - 29 = 14214232619 is a prime.
It is a super-2 number, since 2×142142331312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14214233096 and 14214233105.
It is not an unprimeable number, because it can be changed into a prime (14214233141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27440346 + ... + 27440863.
It is an arithmetic number, because the mean of its divisors is an integer number (2085485980).
Almost surely, 214214233131 is an apocalyptic number.
14214233131 is a deficient number, since it is larger than the sum of its proper divisors (2469654709).
14214233131 is an equidigital number, since it uses as much as digits as its factorization.
14214233131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54881253.
The product of its digits is 1728, while the sum is 25.
Adding to 14214233131 its reverse (13133241241), we get a palindrome (27347474372).
The spelling of 14214233131 in words is "fourteen billion, two hundred fourteen million, two hundred thirty-three thousand, one hundred thirty-one".
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