1421444130001 has 4 divisors (see below), whose sum is σ = 1624507577152. Its totient is φ = 1218380682852.

The previous prime is 1421444129977. The next prime is 1421444130023. The reversal of 1421444130001 is 1000314441241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1421444130001 - 2³³ = 1412854195409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1421444130061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101531723565 + ... + 101531723578.

It is an arithmetic number, because the mean of its divisors is an integer number (406126894288).

Almost surely, 2^{1421444130001} is an apocalyptic number.

It is an amenable number.

1421444130001 is a deficient number, since it is larger than the sum of its proper divisors (203063447151).

1421444130001 is an equidigital number, since it uses as much as digits as its factorization.

1421444130001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203063447150.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1421444130001 its reverse (1000314441241), we get a palindrome (2421758571242).

The spelling of 1421444130001 in words is "one trillion, four hundred twenty-one billion, four hundred forty-four million, one hundred thirty thousand, one".