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14214521024033 = 111292229184003
BaseRepresentation
bin1100111011011001001101…
…1110011110111000100001
31212022220011102002002102212
43032312103132132320201
53330342314340232113
650122021045051505
72664652040102441
oct316662336367041
955286142062385
1014214521024033
1145903876010a0
121716a523b6b95
137c15677b8625
14371db4cd2121
15199b440c30a8
hexced9379ee21

14214521024033 has 4 divisors (see below), whose sum is σ = 15506750208048. Its totient is φ = 12922291840020.

The previous prime is 14214521023999. The next prime is 14214521024131. The reversal of 14214521024033 is 33042012541241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14214521024033 - 238 = 13939643117089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14214521024533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 646114591991 + ... + 646114592012.

It is an arithmetic number, because the mean of its divisors is an integer number (3876687552012).

Almost surely, 214214521024033 is an apocalyptic number.

It is an amenable number.

14214521024033 is a deficient number, since it is larger than the sum of its proper divisors (1292229184015).

14214521024033 is a wasteful number, since it uses less digits than its factorization.

14214521024033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1292229184014.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 14214521024033 its reverse (33042012541241), we get a palindrome (47256533565274).

The spelling of 14214521024033 in words is "fourteen trillion, two hundred fourteen billion, five hundred twenty-one million, twenty-four thousand, thirty-three".

Divisors: 1 11 1292229184003 14214521024033