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142152028127 = 255517556331
BaseRepresentation
bin1000010001100011101…
…0111100111111011111
3111120220211010020100122
42010120322330333133
54312111404400002
6145145335145155
713161442205534
oct2043072747737
9446824106318
10142152028127
115531712878a
12236725151bb
1310535698415
146c4737cd8b
153a6eb146a2
hex2118ebcfdf

142152028127 has 4 divisors (see below), whose sum is σ = 142152839976. Its totient is φ = 142151216280.

The previous prime is 142152028097. The next prime is 142152028147. The reversal of 142152028127 is 721820251241.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142152028127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142152028147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22649 + ... + 533682.

It is an arithmetic number, because the mean of its divisors is an integer number (35538209994).

Almost surely, 2142152028127 is an apocalyptic number.

142152028127 is a deficient number, since it is larger than the sum of its proper divisors (811849).

142152028127 is an equidigital number, since it uses as much as digits as its factorization.

142152028127 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 811848.

The product of its (nonzero) digits is 17920, while the sum is 35.

Adding to 142152028127 its reverse (721820251241), we get a palindrome (863972279368).

The spelling of 142152028127 in words is "one hundred forty-two billion, one hundred fifty-two million, twenty-eight thousand, one hundred twenty-seven".

Divisors: 1 255517 556331 142152028127