Base | Representation |
---|---|
bin | 1100111011011100100001… |
… | …1111101100011011100001 |
3 | 1212022222110101211212212122 |
4 | 3032313020133230123201 |
5 | 3330401130044042423 |
6 | 50122245222234025 |
7 | 2665013060601335 |
oct | 316671037543341 |
9 | 55288411755778 |
10 | 14215410534113 |
11 | 45907a3719198 |
12 | 1717060285915 |
13 | 7c1679b7b459 |
14 | 37205b0bb7c5 |
15 | 199b9722b8c8 |
hex | cedc87ec6e1 |
14215410534113 has 8 divisors (see below), whose sum is σ = 14517962087040. Its totient is φ = 13912862981680.
The previous prime is 14215410534097. The next prime is 14215410534121. The reversal of 14215410534113 is 31143501451241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14215410534113 - 24 = 14215410534097 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (14215410534613) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6827378 + ... + 8662788.
It is an arithmetic number, because the mean of its divisors is an integer number (1814745260880).
Almost surely, 214215410534113 is an apocalyptic number.
It is an amenable number.
14215410534113 is a deficient number, since it is larger than the sum of its proper divisors (302551552927).
14215410534113 is a wasteful number, since it uses less digits than its factorization.
14215410534113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2000247.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 14215410534113 its reverse (31143501451241), we get a palindrome (45358911985354).
The spelling of 14215410534113 in words is "fourteen trillion, two hundred fifteen billion, four hundred ten million, five hundred thirty-four thousand, one hundred thirteen".
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