Base | Representation |
---|---|
bin | 10100101100000111001… |
… | …010101001000010101010 |
3 | 12000220210111202001222211 |
4 | 110230013022221002222 |
5 | 141243223111430114 |
6 | 3005051151035334 |
7 | 204501254021305 |
oct | 24540712510252 |
9 | 5026714661884 |
10 | 1421754405034 |
11 | 4a8a65329827 |
12 | 1ab66680bb4a |
13 | a40bc8c94a2 |
14 | 4cb558d9b3c |
15 | 26eb2e296c4 |
hex | 14b072a90aa |
1421754405034 has 4 divisors (see below), whose sum is σ = 2132631607554. Its totient is φ = 710877202516.
The previous prime is 1421754405031. The next prime is 1421754405061. The reversal of 1421754405034 is 4305044571241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 821385127809 + 600369277225 = 906303^2 + 774835^2 .
It is not an unprimeable number, because it can be changed into a prime (1421754405031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 355438601257 + ... + 355438601260.
Almost surely, 21421754405034 is an apocalyptic number.
1421754405034 is a deficient number, since it is larger than the sum of its proper divisors (710877202520).
1421754405034 is an equidigital number, since it uses as much as digits as its factorization.
1421754405034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 710877202519.
The product of its (nonzero) digits is 268800, while the sum is 40.
Adding to 1421754405034 its reverse (4305044571241), we get a palindrome (5726798976275).
The spelling of 1421754405034 in words is "one trillion, four hundred twenty-one billion, seven hundred fifty-four million, four hundred five thousand, thirty-four".
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