Base | Representation |
---|---|
bin | 1000010001101111010… |
… | …1111011011001100111 |
3 | 111121001020100102111002 |
4 | 2010123311323121213 |
5 | 4312211431330120 |
6 | 145154245503515 |
7 | 13162605626636 |
oct | 2043365733147 |
9 | 447036312432 |
10 | 142201042535 |
11 | 55341865a62 |
12 | 23686a11b9b |
13 | 1054289a026 |
14 | 6c4da9b51d |
15 | 3a74097375 |
hex | 211bd7b667 |
142201042535 has 16 divisors (see below), whose sum is σ = 173078482752. Its totient is φ = 112136640000.
The previous prime is 142201042531. The next prime is 142201042579. The reversal of 142201042535 is 535240102241.
It is not a de Polignac number, because 142201042535 - 22 = 142201042531 is a prime.
It is a super-2 number, since 2×1422010425352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142201042498 and 142201042507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142201042531) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1916447 + ... + 1989263.
It is an arithmetic number, because the mean of its divisors is an integer number (10817405172).
Almost surely, 2142201042535 is an apocalyptic number.
142201042535 is a deficient number, since it is larger than the sum of its proper divisors (30877440217).
142201042535 is an equidigital number, since it uses as much as digits as its factorization.
142201042535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78394.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 142201042535 its reverse (535240102241), we get a palindrome (677441144776).
The spelling of 142201042535 in words is "one hundred forty-two billion, two hundred one million, forty-two thousand, five hundred thirty-five".
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