14221110244034 has 4 divisors (see below), whose sum is σ = 21331665366054. Its totient is φ = 7110555122016.

The previous prime is 14221110243941. The next prime is 14221110244043. The reversal of 14221110244034 is 43044201112241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13937133163009 + 283977081025 = 3733247^2 + 532895^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14221110243988 and 14221110244006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3555277561007 + ... + 3555277561010.

Almost surely, 2^{14221110244034} is an apocalyptic number.

14221110244034 is a deficient number, since it is larger than the sum of its proper divisors (7110555122020).

14221110244034 is an equidigital number, since it uses as much as digits as its factorization.

14221110244034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7110555122019.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 14221110244034 its reverse (43044201112241), we get a palindrome (57265311356275).

The spelling of 14221110244034 in words is "fourteen trillion, two hundred twenty-one billion, one hundred ten million, two hundred forty-four thousand, thirty-four".