142211130321401 has 4 divisors (see below), whose sum is σ = 143033159976612. Its totient is φ = 141389100666192.

The previous prime is 142211130321391. The next prime is 142211130321427. The reversal of 142211130321401 is 104123031112241.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 99747140047801 + 42463990273600 = 9987349^2 + 6516440^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142211130321401 is a prime.

It is a super-3 number, since 3×142211130321401³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142211130621401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 411014827346 + ... + 411014827691.

It is an arithmetic number, because the mean of its divisors is an integer number (35758289994153).

Almost surely, 2^{142211130321401} is an apocalyptic number.

It is an amenable number.

142211130321401 is a deficient number, since it is larger than the sum of its proper divisors (822029655211).

142211130321401 is an equidigital number, since it uses as much as digits as its factorization.

142211130321401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 822029655210.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 142211130321401 its reverse (104123031112241), we get a palindrome (246334161433642).

The spelling of 142211130321401 in words is "one hundred forty-two trillion, two hundred eleven billion, one hundred thirty million, three hundred twenty-one thousand, four hundred one".