1422121133131 has 4 divisors (see below), whose sum is σ = 1423816153200. Its totient is φ = 1420426113064.

The previous prime is 1422121133107. The next prime is 1422121133143. The reversal of 1422121133131 is 1313311212241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1422121133131 is a prime.

It is a super-2 number, since 2×1422121133131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1422121133096 and 1422121133105.

It is not an unprimeable number, because it can be changed into a prime (1422121133161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 847508776 + ... + 847510453.

It is an arithmetic number, because the mean of its divisors is an integer number (355954038300).

Almost surely, 2^{1422121133131} is an apocalyptic number.

1422121133131 is a deficient number, since it is larger than the sum of its proper divisors (1695020069).

1422121133131 is an equidigital number, since it uses as much as digits as its factorization.

1422121133131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1695020068.

The product of its digits is 864, while the sum is 25.

Adding to 1422121133131 its reverse (1313311212241), we get a palindrome (2735432345372).

The spelling of 1422121133131 in words is "one trillion, four hundred twenty-two billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred thirty-one".